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This might be helpful http://geeksforgeeks.org/?p=5036
The solution for the same with ILLUSTRATIVE PICTURES and complete working code in Java at, http://www.technicalypto.com/2010/02/find-common-parent-in
The solution for the same with ILLUSTRATIVE PICTURES and complete working code in Java at, http://www.technicalypto.com/2010/02/find-common-parent-in
1. Go through each nr. in the list 2. store the number in a dictonary as <nr, 1> when found for the first time and increment the frequency entry if f
The idea each char and its location in the string if the char is found again set its location to max value to show is no more interset. then find the
Dictionary<char, int> charLocation = new Dictionary<char, int>(); for(int i=0; i< str.Length; i++) { if(charLocation.Keys.Contains(str[i])
The solution for the same with ILLUSTRATIVE PICTURES and complete working code in Java at, http://technicalypto.blogspot.com/2010/02/find-common-pa
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Iterate down from root. The point at which they split is the common ancestor. Like if p nad q are node values. something like this.. if( node.value=
Iterate down from root. The point at which they split is the common ancestor. Like if p nad q are node values. something like this.. if( node.value=
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